The dissociation constant of n-butyric acid is `1.6 xx 10^(-5)` and the molar conductivity at infinite dilution is `380 xx 10^(-4) Sm^(2) mol^(-1)`. The specific conductance of the `0.01M` acid solution is

Options

A. `1.52 xx 10^(-5) S`
B. 1.52 S
C. `1.52 xx 10^(-3)` S
D. `1.52 xx 10^(-4)` S

Answer

C

Explanation

`Ka = Calpha^(2)`
`Ka = C ((lambda_(m)^( c))/(lambda_(m)^(infty)))^(2)`
`16 xx 10^(-4) = ((lambda_(m)^(C ))/(380 xx 10^(-4)))^(2)`
`lambda_(m)^( c) = 380 xx 10^(-4) xx 4 xx 10^(-2)`
`lambda_(m)^(c ) = 1520 xx 10^(-5) = 1.52 xx 10^(-3)`