The correct order of equivalent conductance at infinite dilution of `LiCl, NaCl` and `KCl` is:

Options

A. `LiCl gt NaCl gt KCl`
B. `KCl gt NaCl gt LiCl`
C. `NaCl gt KCl gt LiCl`
D. `LiCl gt KCl gt NaCl`

Answer

D

Explanation

The ionic size are in the order of :
`Li^(+) lt Na^(+) lt K^(+)`
But hydration of + Li is more than `Na^(+)` and `K^(+)` . So the effective size of ion in the aqueous solutions are as : `Li^(+)(aq) gt Na^(+) (aq) gt K^(+)(aq)`
Mobility of ions will decrease as the size of ions increases and so the equivalent conductance also.
Thus order of equivalent conductance:
`KCl gt NaCl gt LiCl`