At `25^(@)C`, the molar conductances at infinite dilution for the strong electrolytes `NaOH, NaCl " and " BaCl_(2) " are " 248 xx 10^(-4), 126 xx 10^(-4)" and " 280 xx 10^(-4) S m^(2) mol^(-1)` respectively. `Lamda_(m)^(@) Ba (OH)_(2) " in " S m^(2) mol^(-1)`

Options

A. `52.4 xx 10^(-4)`
B. `524 xx 10^(-4)`
C. `402 xx 10^(-4)`
D. `262 xx 10^(-4)`

Answer

B

Explanation

`(280 xx 10^(-4)) + 2(248 xx 10^(-4)) - 2(126 xx 10^(-4))`
`= 524 xx 10^(-4) S m^(2) "mol"^(-1)`