The electrode reactions that takes place at the anode of `CH_(4)-O_(2)` fuel cell is :

Options

A. `2O_(2) + 8H^(+) + 8e^(-) to 4H_(2)O`
B. `CH_(4) + 2H_(2)O to CO_(2) + 8H^(+) + 8e^(-)`
C. `CH_(4) + 2O_(2) to CO_(2) + 2H_(2)O`
D. `2H^(+) + 2e^(-) to H_(2)`

Answer

B

Explanation

Anode reaction: `(CH_(4)+ 2H_(2)O to CO_(2) +8H^(+) + 8e^(-))`
Cathode reaction: `O_(2) + 4H^(+) + 4e to 2H_(2)O xx 2`
`= CH_(4) (g) + 2O_(2)(g) to CO_(2)(g) + 2H_(2)O(l)`