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Zn^(2+) to Zn((s)),E^(@)=-0.76V Cu^(2+...

`Zn^(2+) to Zn_((s)),E^(@)=-0.76V`
`Cu^(2+)toCu_((s)),E^(@)=-0.34V`
which of the following is spontaneous

A

`Zn^(2+) + Cu to Zn + Cu^(2+)`

B

`Cu^(2+) + Zn to Cu + Zn^(2+)`

C

`Zn^(2+) + Cu^(2+) to Zn + Cu`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`Zn^(2+) to Zn_(s), E^(@) = -0.76V`
`Cu^(2+) to Cu_(s), E^(@) = -0.34 V`
A redox reaction is feasible if `E_("cell")` is positive-
`E_("cell") = -0.34 - (-0.76)`
`=-0.34 + 0.76 = +0.42 V`
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