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If the half cel reactions are given as ...

If the half cel reactions are given as
(i) `Fe^(2+)(Aq)+2e^(-)rarr Fe(s),E^(@)=-0.44 V`
(ii) `2H^(+)(sq)+1/2 O_(2)(g)+2e^(-)rarrH_(2)O(l) E^(@)=+1.23 V`
The `E^(@)` for the reaction
`Fe(s)+2H^(+)+1/2O_(2)(g)rarrFe^(2+)(aq)+H_(2)O(l)` will be

A

`+1.67 V`

B

`-1.67 V`

C

`+0.79 V`

D

`-0.79 V`

Text Solution

Verified by Experts

The correct Answer is:
A
Subtracting equation (i) from (ii) we will get equation (iii)
`Fe_(s) + 2H^(+) + 1/2 O_(2) to Fe^(2+) (aq) + H_(2)O(l)`….. (iii)
So, `E^(@) = E_(2)^(@) -E_(1)^(@)`
`+ 1.23 - (-0.44) = +1.67 V`
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