If an element A is placed in electrochemicals series above element B but below element C, then the order of oxidation power of elements-

Options

A. `A gt B gt C`
B. `C gt B gt A`
C. `C gt A gt B`
D. `B gt A gt C`

Explanation

To determine the order of oxidation power of elements A, B, and C based on their positions in the electrochemical series, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Electrochemical Series**: The electrochemical series is a list of elements arranged according to their standard electrode potentials. Elements higher in the series have a greater tendency to be reduced (gain electrons), while those lower in the series have a greater tendency to be oxidized (lose electrons).

2. **Position of Elements**: According to the problem:
- Element A is placed above element B in the electrochemical series.
- Element C is placed above element A in the electrochemical series.

3. **Determining Oxidation Power**:
- Since element A is above element B, it means that A has a higher reduction potential than B. Therefore, A is less likely to be oxidized compared to B, which means B has a higher oxidation power than A.
- Similarly, since element C is above element A, C has a higher reduction potential than A. Thus, C is also less likely to be oxidized compared to A, meaning A has a higher oxidation power than C.

4. **Arranging the Elements**: Based on the above points:
- B has the highest oxidation power (most likely to be oxidized).
- A has the next highest oxidation power.
- C has the lowest oxidation power (least likely to be oxidized).

5. **Final Order of Oxidation Power**: Therefore, the order of oxidation power from highest to lowest is:
- B > A > C

### Final Answer:
The order of oxidation power of the elements is: **B > A > C**.