Home
Class 12
CHEMISTRY
Using tha data given below is reducing p...

Using tha data given below is reducing potenial.
`E_(Cr_2O_7^(2-)//Cr^(3+))^@`=1.33 V , `E_(Cl_2//Cl^-)^@`=1.36 V
`E_(MnO_4^(-)//Mn^(2+))^@`=1.51 V , `E_(Cr^(3+) // Cr)^@` =- 0.74 V
find out which of the following is the strongest oxidising agent.

A

`Cl^(-)`

B

Cr

C

`Cr^(3+)`

D

`Mn^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
B

Here, out of given four options standard reduction potential of chromium has highest negative value hence most powerful reducing agent is chromium.
Promotional Banner

Similar Questions

Explore conceptually related problems

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Mark the strongest oxidising agent.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Mark the strongest reducing agent.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable oxidised species.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable ion in its reduced forms

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V In which option the order of reducing power is correct?