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The electrode pptenticals for Cu^(2+)...

The electrode pptenticals for
` Cu^(2+) (aq) +e^(-) rarr Cu^+ (aq) `
and ` Cu^+ (aq) + e^- rarr Cu (s)`
are `+ 0.15 V` and ` +0. 50 V` repectively. The value of `E_(cu^(2+)//Cu)^@` will be.

A

`0.150 V`

B

`0.500 V`

C

`0.325 V`

D

`0.650 V`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaG_3 = DeltaG_1+ DeltaG_2`
`implies - 2FE^@ = -1F xx 0.15 + (-1F xx 0.50)`
`implies -2 FE^@ = -0.1 - 0.50F`
`implies - 2FE^@ = -F(0.15 + 0.50)`
`:. E^@ = (0.65)/2 = 0.325` volt.
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