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For the electrochemical cell, M|M^(+) ||...

For the electrochemical cell, `M|M^(+) ||X^(-)|X`, `E_(M^(+)//M)^(@) = 0.44 V` and `E_(X//X^(-))^(@) = 0.33 V`. From this data we can deduce that :

A

`M + X rarr M^(+) + X^(-)` is the spontaneous reaction

B

`M + X rarr M^(-) rarr X` is the spontaneous reaction

C

`E_("cell") = 0.77 V`

D

`E_("cell") = -0.77 V`

Text Solution

Verified by Experts

The correct Answer is:
B
For the given cell `M||M^(+)||X^(-) || X` , the cell reaction is derived as follows:
R.H.S. : reduction `X + e^(-) rarr X^(-)` …..(i)
L.H.S. : Oxidation `M rarr M^(+) + e^(-)` …..(ii)
Add (i) and (ii) `M + X rarr M^(+) + X^(-)`
The cell potential = -0.11V
Since `E_("cell")=-ve` the cell reaction derived above is not spontaneous. In fact, the reverse reaction will occur spontaneously.
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