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Electrode potential for Mg electrode var...

Electrode potential for `Mg` electrode varies according to the equation
`E_(Mg^(2+)|Mg)=E_(Mg^(2+)|Mg)^(ϴ) -(0.059)/2 "log" 1/([Mg^(2+)])`
The graph of `E_(Mg^(2+)|Mg) vs log [Mg^(2+)]` is

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
B

Electrode potential for Mg electrode varies according to the equation
`E_(Mg^(2+)//Mg)=E_("Mg"^(2+)//Mg)-(0.059)/(2)log""(1)/([Mg^(2+)])`
`E_(Mg^(2+)//Mg)=E_("Mg"^(2+)//Mg)^(@)+(0.059)/(2)[Mg^(2+)]`
`E_(Mg^(2+)//Mg)=(0.059)/2log[Mg^(2+)]+E_("Mg"^(2+)//Mg)^(@)`
This equation represents equation of straight line. It can be correlated as
`{:(E_(Mg^(2+)//Mg),=((-0.059)/2),log[Mg^(2+)],+E_(Mg^(2+)//Mg)),(uarr,uarr,uarr,uarr),(Y,M,X,+C):}`
So, intercept `(C)=E_(Mg^(2+)//Mg)^(@)`
Thus equation can be diagrammatically represented as.
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