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If Zn^(2+)//Zn electrode is diluted 100 ...

If `Zn^(2+)//Zn` electrode is diluted 100 times, then the charge in reduction potential is

A

Increase of 59mV

B

Decrease of 59mV

C

Increase of 29.5mV

D

Decrease of 29.5mV

Text Solution

Verified by Experts

The correct Answer is:
A

`=0.34 -(0.059)/nlog""1/C=-(0.059)/2log""1/100`
`=-(0.059)/2(-2) =0.059V = 59mV ` (increase).
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