Home
Class 12
CHEMISTRY
The e.m.f. of the following cell at 25^(...

The e.m.f. of the following cell at `25^(@)C` is _________.
`Fe_((s))|FeSO_(4(aq)) (0.1M)||CuSO_(4(aq))(0.01M)|Cu_(s)`
`(E_(Fe^(2+)||Fe)^(@)=-0.44 V and E_(cu^(2+)|Cu)^(@)=0.337V)`

A

x cannot be predict

B

x = 0.01M

C

`x gt 0.01M`

D

`x lt 0.01M`

Text Solution

Verified by Experts

The correct Answer is:
B

If a solution contains two or more cations, the cation to be deposited on the cathode is the one which has higher reduction potential. Here the reaction will be `Fe + Cu^(2+) rarr Fe^(2+) + Cu`
`E_("cell") =E_("cell")^@-(0.0591)/nlog""([Fe^(2+)])/([Cu^(2+)])`
`0.78=0.78-(0.0591)/nlog""([Fe^(2+)])/([Cu^(2+)])`
or , `0=log""x/(0.01) implies x/(0.01)implies x = 0.01 `
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate emf of the following cell reaction at 2968 K : Ni(s)//Ni^(2+)(0.01 M) || Cu^(2+)(0.1 M)//Cu(s) [Given E_(Ni^(2+)//Ni)^(@)=-0.25" V ",E_(Cu^(2+)//Cu)^(@)=+0.34 " V " ] Write the overall cell reaction.

Calculate the e.m.f of the cell Mg(s)//Mg^(2+)(0.1 M)||Cu^(2+)(1.0xx10^(-3) M)//Cu(s) Given E_(Cu^(2+)//Cu)^(@)=+0.34 V and E_(Mg^(2+)//Mg)^(@)=-2.37 V

Calculate EMF of following cell at 298 K Zn|ZnSO_(4) (0.1 M) ||CuSO_(4) (1.0 M)|Cu (s) if E_(cell) = 2.0 V

Find the e.m.f. of the cell, Mg(s)//Mg^(2+)(0.01 M) || Cu^(2+)(aq)(0.0001 M)//Cu(s) "Given" E_(Mg^(2+)//Mg)^(@)=-2.37 " volts" , E_(Cu^(2+)//Cu)^(@)=+0.34" volts" .

Calculate E_(cell)^(0) of (at 298K) Zn(s)//ZnSO_(4)(aq)||CuSO_(4)(aq)//Cu(s) given that E_(Zn//Zn^(2+)(aq))^(0)=0.76V E_(Cu(s)//Cu^(2+)(aq))^(0)=-0.34V