How many grams of cobalt metal will be deposited when a solution of cobat (II) chloride is electrolyzed with a current of 10 amperes for 109 minutes? (1 Faraday = 96,500C, Atomic mass of Co= 59u)

Options

A. `4.0`
B. `20.0`
C. `40.0`
D. `0.66`

Answer

B

Explanation

`w= Zlt`
`therefore w= (E_(B) xx l t)/(96500) ( therefore E_(B)= (M_(B))/(Z)= (59)/(2))`
`w= (59)/(2) xx (10 xx 109 xx 60)/(96500)= w= 19.9`