`4.5 g` of aluminium (at mass `27 u`) is deposited at cathode from `Al^(3+)` solution by a certain quantity of electric charge. The volume of hydrogen gas produced at `STP` from `H^(+)` ions in solution by the same quantity of electric charge will be:

Options

A. 22.4L
B. 44.8L
C. 5.6L
D. 11.2L

Answer

C

Explanation

Eq. of Al = eq. of `H_92)`
`(4.5)/((27)/(3))` =eq.of Al, `(4.5)/(9)`= e.q of `H_(2)`
`2H^(+) +2e^(-) rarr H_(2)`
eq. of `H_(2)`= Number of moles `xx`n factor
`0.5 = n_(H_(2)) xx 2`
`V_(H_(2))= (0.5)/(2) xx 22.4 , V_(H_(2))= 5.6L`