The resistance of `0. 01 N NaCl` solution at `25^@C` is `200 Omega` . Cell constant of conductivity cell is ` 1 cm^(-1)` . The equivalent conductance is .

Options

A. `5 xx 10^(2) Omega^(-1) cm^(2) eq^(-1)`
B. `6 xx 10^(3) Omega^(-1) cm^(2) eq^(-1)`
C. `7 xx 10^(4) Omega^(-1) cm^(2) eq^(-1)`
D. `8 xx 10^(5) Omega^(-1) cm^(2) eq^(-1)`

Answer

A

Explanation

`lamda= k xx V= (1)/(R) xx (l)/(a) xx V= (1)/(200) xx 1 xx 10,000`
`=5 xx 10^(2) Omega^(-1) cm^(2) eq^(-1)`