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The standard oxidation potentials, E^(@)...

The standard oxidation potentials, `E^(@)`, for the half reactions are as,
`Zn rarr Zn^(2+) + 2e^(-), " " E^(@) = + 0.76` volt
`Fe rarr Fe^(2+) + 2e^(-), " " E^(@) = +0.41` volt
The emf of the cell, `Fe^(2+) + Zn rarr Zn^(2+) + Fe` is:

A

`-0.35V`

B

`+0.35V`

C

`+1.17V`

D

`-1.17V`

Text Solution

Verified by Experts

The correct Answer is:
B
In this reaction
`EMF= E_("cathode")- E_("anode")`
`= -0.41- (-0.76)`
=+0.35V
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