For the reduction of silver ions with copper metal, the standard cell potential was foound to be `+0.46 V` at `25^(@) C`. The value of standard Gibbs energy, `DeltaG^(@)` will be `(F = 96,500C mol^(-1))`:

Options

A. `-98.0kJ`
B. `-89.0kJ`
C. `-89.0J`
D. `-44.5kJ`

Answer

B

Explanation

`2Ag^(+)(aq) + Cu(S) rarr 2Ag(s) + Cu^(2+)(aq)` n=2
`Delta G= -nFE_("cell")`
`Delta G= -2 xx 96500 xx 0.46J`
`Delta G= -88.78kJ= -89kJ`