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The oxidation potential of a hydrogen el...

The oxidation potential of a hydrogen electrode at `pH = 10` and `P_(H_(2)) =1` is

A

`0.059` V

B

`0.59` V

C

`0.00` V

D

`0.51 V`

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(OP)= E_(OP)^(@)- (0.059)/(1) "log" ([H^(+)])/(p_(H_(2)))`
`therefore [H^(+)] = 10^(-10), p_(H_(2))=1` atm, `E_(OP)= 0.59V`
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