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Standard reduction potentails of the hal...

Standard reduction potentails of the half reactions are given below:
`F_(2)(g)+2e^(-) rarr 2F^(-)(aq.),, E^(ɵ)= +2.87`
`Cl_(2)(g)+2e^(-) rarr 2Cl^(-)(aq.),, E^(ɵ)= +1.36 V`
`Br_(2)(g)+2e^(-) rarr 2Br^(-)(aq.),, E^(ɵ)= +1.09 V`
`I_(2)(s)+2e^(-) rarr 2l^(-)(aq.),, E^(ɵ)= +0.54 V`
The strongest oxidizing and reducing agents respectively are:

A

`F_(2) and l_(-)`

B

`Br_(2) and Cl^(-)`

C

`Cl_(2) and Br^(-)`

D

`Cl_(2) and l_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`E^(@)` more positive, more easily it will reduce
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Standard reduction potentials of the half reactions are given below {:(F_(2(g))+2e^(-) rarr 2F^(-)""_((aq)),,E^(@)=+2.85V), (Cl_(2(g))+2e^(-) rarr 2Cl^(-)""_((aq)),, E^(@)=+1.36V), (Br_(2(l))+2e^(-) rarr 2Br^(-)""_((aq)),,E^(@)=+1.06V), (l_(2(s))+2e^(-) rarr 2l^(-)""_((aq)),, E^(@)=+0.53V):} The strongest oxidising and reducing agents respectively are

Standrd reduction potentials of the half reactions are given below : F_2 (g) +re^- rarr 2 F^(-) (aq) E^@ = + 2.85 V Cl_2 (g) +2e^- rarr 2 Cl^-(aq) , E^2 = + 1.36 V Br _2 (i) + 2 e^- rarr 2Br (aq) , E^2 = + 1. 06 V I_2 (s) + 2 e^- rarr 2I^(-) (aq) , E^2 = + . 53 V . The strongest oxidizing and reducing agents respectively

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