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On the basis of the following E^(@) valu...

On the basis of the following `E^(@)` values, the stongest oxidizing agent is `[Fe(CN)_(6)]^(4-) rarr [Fe(CN)_(6)]^(3-)+e^(-), E^(@) = -0.35 V`
`Fe^(2+) rarr Fe^(3+)+e^(-), E^(@) = -0.77 V`

A

`Fe^(3+)`

B

`[Fe(CN)_(6)]^(3-)`

C

`[Fe(CN)_(6)]^(4)`

D

`Fe^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
A
`[Fe(CN)_(6)]^(4-) rarr [Fe(CN)_(6)]^(3-) + e^(-), E^(@)= -0.35V`
`[Fe(CN)_(6)]^(3-) + e^(-) rarr [Fe(CN)_(6)]^(4-), E^(@)= +0.35V`
`Fe^(2+) rarr Fe^(3+) + e6(-), E^(@)= -0.77V`
`Fe^(3+) + e^(-) rarr Fe^(2+), E^(@)= +0.77V`
The value of reduction potentia `E_(Fe^(3+)//Fe^(2+))^(@)` is highest. So `Fe^(3+)` will act as the strongest oxidizing agent.
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