`P_4 O_6` reacts with water to give

Options

A. `H_3 PO_3`
B. `H_4 P_2 O_7`
C. `HPO_3`
D. `H_3 PO_4`

Explanation

To solve the problem of what \( P_4O_6 \) reacts with water to produce, we can follow these steps:

### Step 1: Identify the Reactants
The reactant in this case is \( P_4O_6 \) (tetraphosphorus hexoxide), which is a phosphorus oxide.

### Step 2: Write the Reaction with Water
When \( P_4O_6 \) reacts with water, it undergoes hydrolysis. The general reaction can be written as:
\[ P_4O_6 + H_2O \rightarrow ? \]

### Step 3: Determine the Product
The hydrolysis of \( P_4O_6 \) leads to the formation of phosphorous acid, which has the formula \( H_3PO_3 \).

### Step 4: Balance the Reaction
To balance the reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation is:
\[ P_4O_6 + 6H_2O \rightarrow 4H_3PO_3 \]

### Step 5: Conclusion
Thus, when \( P_4O_6 \) reacts with water, it produces phosphorous acid, \( H_3PO_3 \).

### Final Answer
The product of the reaction of \( P_4O_6 \) with water is \( H_3PO_3 \) (phosphorous acid).

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