The oxidation number of sulphur is +4 in

Options

A. `H_(2)S`
B. `CS_(2)`
C. `Na_(2)SO_(4)`
D. `Na_(2)SO_(3)`

Explanation

To determine the oxidation number of sulfur in a compound, we can follow these steps:

### Step 1: Identify the compound
First, we need to identify the compound in which we want to find the oxidation number of sulfur. For this example, let's consider sulfur dioxide (SO₂).

### Step 2: Assign oxidation numbers to known elements
In compounds, we assign oxidation numbers based on certain rules. Oxygen typically has an oxidation number of -2.

### Step 3: Set up the equation
In sulfur dioxide (SO₂), we have one sulfur atom and two oxygen atoms. The overall charge of the compound is neutral (0). We can set up the equation as follows:

Let the oxidation number of sulfur be \( x \).

The equation will be:
\[ x + 2(-2) = 0 \]

### Step 4: Solve for the oxidation number of sulfur
Now we can solve the equation:
\[ x - 4 = 0 \]
\[ x = +4 \]

### Conclusion
Thus, the oxidation number of sulfur in sulfur dioxide (SO₂) is +4.

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