Among `Cl^-, Br^-, I^-`, the correct order for being oxidise to dihalogen is

Options

A. `I^(-) gt Cl^(-)gtbr^(-)`
B. `Cl^(-)gtBr^(-)gtI^(-)`
C. `I^(-)gtBr^(-)gtCl^(-)`
D. `Br^(-)gtI^(-)gtCl^(-)`

Answer

C

Explanation

Due to large size and less electromagnetic force on the valence electrons, `I^(-)` can release an electron and oxidize to `I_(2)` most easily.