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Assertion: N(2)H(4) cannot reduce S(2)O(...

Assertion: `N_(2)H_(4)` cannot reduce `S_(2)O_(3)^(2-)`
Reason : `S_(2)O_(3)^(2-)` is converted to `S_(4)O_(6)^(2-)`

A

If both assertion and reason are true and the reason is the correct explanation of the assertion

B

If both assertion and reason are true but reason is not the correct explanation of the assertion.

C

If assertion is true but reason is false

D

If the assertion and reason both are false.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the assertion and reason provided in the question, we will break down the concepts involved and provide a step-by-step solution. ### Step 1: Understand the Assertion The assertion states that \(N_2H_4\) (hydrazine) cannot reduce \(S_2O_3^{2-}\) (thiosulfate ion). **Hint:** Recall the properties of hydrazine and its reducing capabilities. ### Step 2: Analyze the Reducing Agent Hydrazine (\(N_2H_4\)) is known to be a reducing agent, but its effectiveness depends on the species it is reacting with. **Hint:** Consider what makes a good reducing agent and the nature of the thiosulfate ion. ### Step 3: Understand the Reason The reason states that \(S_2O_3^{2-}\) is converted to \(S_4O_6^{2-}\) (tetrathionate ion). This transformation typically occurs in reactions involving oxidation. **Hint:** Think about the oxidation states of sulfur in both thiosulfate and tetrathionate. ### Step 4: Evaluate the Reaction When \(S_2O_3^{2-}\) is oxidized, it can form \(S_4O_6^{2-}\). However, for \(N_2H_4\) to reduce \(S_2O_3^{2-}\), it would need to provide electrons, which it cannot do effectively in this case. **Hint:** Consider the electron transfer process and the stability of the products formed. ### Step 5: Conclusion on Assertion and Reason Both the assertion and the reason are true: - The assertion is correct because \(N_2H_4\) cannot reduce \(S_2O_3^{2-}\). - The reason is also correct as \(S_2O_3^{2-}\) can be converted to \(S_4O_6^{2-}\) through oxidation. However, the reason does not adequately explain the assertion, as it does not address why \(N_2H_4\) cannot act as a reducing agent in this case. **Final Conclusion:** The correct option would be that both assertion and reason are true, but the reason is not the correct explanation for the assertion. ### Summary - Assertion: True - Reason: True - Explanation: The reason does not correctly explain the assertion.

To analyze the assertion and reason provided in the question, we will break down the concepts involved and provide a step-by-step solution. ### Step 1: Understand the Assertion The assertion states that \(N_2H_4\) (hydrazine) cannot reduce \(S_2O_3^{2-}\) (thiosulfate ion). **Hint:** Recall the properties of hydrazine and its reducing capabilities. ### Step 2: Analyze the Reducing Agent ...
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I_(2)+S_(2)O_(3)^(2-) to I^(-)+S_(4)O_(6)^(2-)

In which of the following pairs,each compound has same average oxidation state for S-atom? (A) S_(2)O_(3)^(2-) and S_(4)O_(6)^(2-) (B) S_(2)O_(7)^(2-) and S_(2)O_(8)^(2-) (C) S_(4)O_(6)^(2-) and S_(2)O_(7)^(2-) (D) S_(4)O_(6)^(2-) and S_(2)O_(8)^(2-)

S_(2)O_(3)^(2-) and S^(2-) cannot be distinguished by:

In which pair of ions both species contains S-S bond? (A) S_(2)O_(6)^(2-) , S_(2)O_(3)^(2-) (B) S_(2)O_(4)^(2-) , S_(2)O_(7)^(2-) , (C) S_(2)O_(7)^(2-) , S_(2)O_(2)^(2-) , (D) S_(2)O_(7)^(2-) , S_(2)O_(3)^(2-)

Three different solutions of oxidising agents KMnO_(4),K_(2)Cr_(2)O_(7) " and "I_(2) is titrated separately with 0.158 gm of Na_(2)S_(2)O_(3) . If molarity of each oxidising agent is 0.1 M and reactions are : I. MnO_(4)^(-)+S_(2)O_(3)^(2-) toMnO_(2)+SO_(4)^(2-) II CrO_(7)^(2-)+S_(2)O_(3)^(2-) to Cr^(3+)+SO_(4)^(2-) III. I_(2)+S_(2)O_(3)^(2-) to S_(4)O_(6)^(2-)+I^(-)

H_(4)underline(S_(2))O_(6)+H_(2)O to H_(2)SO_(3)+H_(2)SO_(4)

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