`CH-=CH+H_2O underset(HgSO_4)overset(H_2SO_4)to A underset(300^@C)overset(H_2//Ni)to B`. What are A and B

Options

A. `CH_3CHO` and `CH_3CH_2OH`
B. HCHO and `CH_3CH_2OH`
C. `CH_3CH_2OH` and `CH_3CH_2CHO`
D. HCHO and `CH_3CHO`

Explanation

To solve the question, we will analyze the reactions step by step.

### Step 1: Identify the starting material
The starting material is an alkyne, specifically 1-butyne (CH≡CH).

### Step 2: Hydration of the alkyne
The reaction CH≡CH + H2O in the presence of HgSO4 and H2SO4 is a hydration reaction. This reaction follows Markovnikov's rule, where water adds across the triple bond.

- The product of this reaction is an aldehyde.
- In this case, the product A is **butanal (C3H7CHO)**.

### Step 3: Reduction of the aldehyde
The next step involves the reduction of the aldehyde (butanal) using hydrogen gas (H2) in the presence of nickel (Ni) at 300°C.

- The reduction of an aldehyde typically yields a primary alcohol.
- The product B from this reduction is **butanol (C3H7OH)**.

### Summary of Products
- **A (Product after hydration)**: Butanal (C3H7CHO)
- **B (Product after reduction)**: Butanol (C3H7OH)

### Final Answer
- A = Butanal (C3H7CHO)
- B = Butanol (C3H7OH)