The major product of the following reaction is `CH_3-underset(CH_3)underset(|)overset(CH_3)overset(|)C-CH_2-OH overset(H_2SO_4)to`

Options

A. `(CH_3)_2C=CH_2`
B. Butane-2-one
C. `(CH_3)_2overset(OH)overset(|)C-CHO`
D. Isobutyraldehyde

Explanation

To determine the major product of the given reaction, we will analyze the reaction step by step.

### Step 1: Identify the Reactants
The reactant is a diol, which contains two hydroxyl (-OH) groups. The structure can be represented as:
\[ \text{CH}_3-\text{C}(\text{OH})(\text{CH}_3)-\text{CH}_2-\text{OH} \]

### Step 2: Understand the Reaction Conditions
The reaction is carried out in acidic conditions (using \( \text{H}_2\text{SO}_4 \)). Acidic conditions will protonate the hydroxyl groups, making them better leaving groups.

### Step 3: Protonation of the Hydroxyl Group
Under acidic conditions, one of the hydroxyl groups will be protonated to form a better leaving group:
\[ \text{CH}_3-\text{C}(\text{OH}_2^+)(\text{CH}_3)-\text{CH}_2-\text{OH} \]

### Step 4: Formation of Carbocation
When the protonated hydroxyl group leaves, it forms a carbocation. The leaving of water leads to the formation of a more stable tertiary carbocation:
\[ \text{CH}_3-\text{C}^+(\text{CH}_3)-\text{CH}_2 \]

### Step 5: Rearrangement (Hydride Shift)
To stabilize the carbocation, a hydride shift occurs. A hydrogen atom from the adjacent carbon shifts to the positively charged carbon, leading to a more stable carbocation:
\[ \text{CH}_3-\text{C}(\text{CH}_3)-\text{C}^+(\text{OH}) \]

### Step 6: Dehydration
The next step involves the loss of a proton from the hydroxyl group, resulting in the formation of a double bond:
\[ \text{CH}_3-\text{C}(\text{CH}_3)-\text{C}=\text{O} \]

### Step 7: Identify the Major Product
The final product after dehydration is isobutyraldehyde:
\[ \text{CH}_3-\text{C}(\text{CH}_3)=\text{C}(\text{O})-\text{H} \]

### Conclusion
The major product of the reaction is isobutyraldehyde.

### Final Answer
The major product is **isobutyraldehyde**.

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