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CH(2)=CH-(CH(2))(5)COOH underset(HBr)ove...

`CH_(2)=CH-(CH_(2))_(5)COOH underset(HBr)overset("Peroxide")to Z` where Z is _________.

A

`CH_(3)-underset(Br)underset(|)CH-(CH_(2))_(5)COOH`

B

`BrCH_(2)-(CH_(2))_(5)-CH_(2)OH`

C

`CH_(2)= CH-C

D

`C_(6)H_(5)COOH`

Text Solution

Verified by Experts

The correct Answer is:
B
`CH_(2)= CH-(CH_(2))_(5)COOH underset(HBr)overset("peroxide")to underset(Br)underset(|)CH_(2)-(CH_(2))_(6)-COOH`
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Knowledge Check

  • The principal organic product formed in the reaction CH_(2) = CH (CH_(2))_(8) COOH + HBr overset("Peroxide")rarr is

    A
    `CH_(3) CH (Br) (CH_(2))_(8) COOH`
    B
    `CH_(2) = CH (CH_(2))_(8) COBr`
    C
    `CH_(2)Br (CH_(2))_(9) COOH`
    D
    `CH_(2) = CH (CH_(2))_(7) CHBr COOH`

  • CH_(2)=CH-CH_(2)-CH_(2)-C-=CH underset((1 eq))overset(HBr)to Product is

    A
    `BrCH_(2)-CH_(2)-CH_(2)-CH_(2)-C-=CH`
    B
    `CH_(2)=CH-CH_(2)-CH_(2)-CH=CH-Br`
    C
    `CH_(2)=CH-CH_(2)-CH_(2)-underset(Br)underset(|)C=CH_(2)`
    D
    `CH_(3)-underset(Br)underset(|)CH-CH_(2)-CH_(2)-C-=CH`

  • The principal organic product formed in the reaction given below is: CH_(2)=CH(CH_(2))_(8)COOH + HBr overset("peroxide")(to).......

    A
    `CH_(3)-CHBr(CH_(2))_(8)COOH`
    B
    `CH_(2)=CH(CH_(2))_(8)COBr`
    C
    `CH_(2)BrCH_(2)(CH_(2))_(8)COOH`
    D
    `CH_(2)=CH(CH_(2))_(7)CHBrCOOH`