Silver benzoate reacts with bromine to form

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Explanation

To solve the problem of what silver benzoate reacts with bromine to form, we can follow these steps:

### Step 1: Identify the Reactants
We start with silver benzoate (AgC₆H₅COO) as our reactant. It is a silver salt of benzoic acid.

### Step 2: Understand the Reaction Conditions
The reaction involves bromine (Br₂) and is typically carried out in the presence of a base, such as sodium hydroxide (NaOH).

### Step 3: Recognize the Reaction Type
The reaction between silver benzoate and bromine can be classified as a halogenation reaction. In this case, bromine will replace the hydrogen atom in the aromatic ring of benzoate.

### Step 4: Identify the Products
When silver benzoate reacts with bromine, it leads to the formation of bromobenzene (C₆H₅Br) and carbon dioxide (CO₂) as a byproduct. The silver ion (Ag⁺) will also be released in the reaction.

### Step 5: Write the Balanced Reaction
The balanced chemical equation for the reaction can be written as follows:
\[ \text{AgC}_6\text{H}_5\text{COO} + \text{Br}_2 \rightarrow \text{C}_6\text{H}_5\text{Br} + \text{AgBr} + \text{CO}_2 \]

### Conclusion
The major product formed from the reaction of silver benzoate with bromine is bromobenzene (C₆H₅Br).

### Final Answer
Bromobenzene is formed when silver benzoate reacts with bromine.

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