`C_(5)H_(13)N` reacts with `HNO_(2)` to give an optically active alcohol The compound is

Options

A. Pentan–1–amine
B. Pentan–2–amine
C. N, N–dimethylpropan–2–amine
D. N–methylbutan–2– amine

Answer

B

Explanation

`HNO_(2)` reacts to give an alcohol means the compound is primary amine `C_(5)H_(13)N` is thus `C_(5)H_(11)NH_(2)`
Optically active alcohol means `C_(5)H_(11)`-segment contains a chiral carbon.
`CH_(3)- CH_(2)- CH_(2)- underset(underset(CH_(3))(|))overset(overset(H)(|))(C^(**)) - NH_(2)`