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When aniline is nitrated with nitrating ...

When aniline is nitrated with nitrating mixture in ice cold condition, the major product obtained is

A

p-nitroaniline

B

2,4-dinitroaniline

C

o-nitroaniline

D

m-nitroaniline

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The correct Answer is:
To solve the question regarding the nitration of aniline in ice-cold conditions, we can follow these steps: ### Step 1: Understand the Reactants Aniline (C6H5NH2) is an aromatic amine where the amino group (-NH2) is directly attached to a benzene ring. The nitrating mixture typically consists of concentrated nitric acid (HNO3) and concentrated sulfuric acid (H2SO4). **Hint:** Identify the functional groups present in the reactants and their positions on the benzene ring. ### Step 2: Identify the Reaction Conditions The reaction is performed under ice-cold conditions (0 degrees Celsius). This is important because temperature affects the reactivity of the aromatic compound and the position of substitution. **Hint:** Recall how temperature influences electrophilic aromatic substitution reactions. ### Step 3: Determine the Electrophile In the nitration process, the electrophile is the nitronium ion (NO2+), which is generated from the reaction of nitric acid and sulfuric acid. **Hint:** Remember that the electrophile in nitration is crucial for determining the position of substitution on the benzene ring. ### Step 4: Analyze the Directing Effects The amino group (-NH2) is a strong activating group and is ortho/para-directing. This means that it will direct incoming electrophiles to the ortho and para positions relative to itself on the benzene ring. **Hint:** Consider how substituents on the benzene ring influence the positions where new groups can be added. ### Step 5: Identify the Major Product Since the reaction occurs in ice-cold conditions, the para product is favored over the ortho product due to steric hindrance. Therefore, when aniline is nitrated, the major product will be para-nitroaniline (C6H4(NH2)(NO2) at the para position). **Hint:** Think about steric factors and how they influence the stability of the products formed. ### Conclusion The major product obtained when aniline is nitrated with a nitrating mixture in ice-cold conditions is **para-nitroaniline**. **Final Answer:** Para-nitroaniline. ---

To solve the question regarding the nitration of aniline in ice-cold conditions, we can follow these steps: ### Step 1: Understand the Reactants Aniline (C6H5NH2) is an aromatic amine where the amino group (-NH2) is directly attached to a benzene ring. The nitrating mixture typically consists of concentrated nitric acid (HNO3) and concentrated sulfuric acid (H2SO4). **Hint:** Identify the functional groups present in the reactants and their positions on the benzene ring. ### Step 2: Identify the Reaction Conditions ...
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ERRORLESS-ORGANIC COMPOUNDS CONTAINING NITROGEN-NCERT Based Questions (Aniline)
  1. Which of the following is more basic than aniline? .

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  2. The product of reaction between anilne and acetic andyide is:

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  3. When aniline is nitrated with nitrating mixture in ice cold condition,...

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  4. In hydrolysis of aniline, the reagent used is

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  5. The correct increasing order of basic strength for the following compo...

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  6. The gas evolved when methylamine reacts with nitrous acid is

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  7. Triaminobenzene is a .

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  8. The reaction of chloroform with alcoholic KOH and p- toluidine forms

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  9. For the preparation of p-nitroiodobenzene from p-nitroaniline, the bes...

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  10. In acid medium nitrobenzene is reduced to aniline as shown in the reac...

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  11. In the series of reaction C(6)H(5)NH(2)underset(0-5^(@)C)overset(NaN...

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  12. Anilinum hydrogensulphate on heating with sulphuric acid at 453-473K p...

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  13. Aniline is treated wi.th bromine water to give an organic compound X w...

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  14. Chloroform when treated with aniline and alcoholic KOH forms -

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  15. Aniline when treated with conc. HNO3 gives

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  16. Which one is less alkaline?

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  17. Among the following the strongest base is

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  18. Aniline and methyl amine can be differentiated by

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  19. Mixture of benzene and aniline can be separated by:

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  20. C(6)H(5)NH(2)overset(NaNO(2)//HCl)rarrXoverset(Cu(2)(CN)(2))rarrYovers...

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