Action of `NaNO_(2)` + dil HCl on `ArNH_(2)` yields `ArN_(2)^(+)Cl^(-)` A similar reaction with cyclohexylamine will yield

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Explanation

To solve the question regarding the action of `NaNO₂` and dilute `HCl` on `ArNH₂` (aromatic amine) and its comparison with cyclohexylamine, we can follow these steps:

### Step 1: Understand the Reaction of Aromatic Amines
When an aromatic amine (ArNH₂) is treated with sodium nitrite (NaNO₂) in the presence of dilute hydrochloric acid (HCl), it forms an aromatic diazonium salt. The general reaction can be represented as follows:

\[ \text{ArNH}_2 + \text{NaNO}_2 + \text{HCl} \rightarrow \text{ArN}_2^+ \text{Cl}^- + \text{H}_2\text{O} \]

### Step 2: Identify the Product of Cyclohexylamine Reaction
Cyclohexylamine (C₆H₁₁NH₂) is a non-aromatic amine. When cyclohexylamine is treated with sodium nitrite and dilute hydrochloric acid, the reaction does not yield a diazonium salt because cyclohexylamine is aliphatic. Instead, the reaction leads to the formation of cyclohexene and nitrogen gas.

The reaction can be summarized as follows:

\[ \text{C}_6\text{H}_{11}\text{NH}_2 + \text{NaNO}_2 + \text{HCl} \rightarrow \text{C}_6\text{H}_{10} + \text{N}_2 + \text{NaCl} + \text{H}_2\text{O} \]

### Step 3: Write the Final Products
The final products of the reaction with cyclohexylamine are:
- Cyclohexene (C₆H₁₀)
- Nitrogen gas (N₂)
- Sodium chloride (NaCl)
- Water (H₂O)

### Conclusion
Thus, the action of `NaNO₂` and dilute `HCl` on cyclohexylamine yields cyclohexene, nitrogen gas, sodium chloride, and water.