Home
Class 12
CHEMISTRY
F(2)C = CF(2) is a monomer of...

`F_(2)C = CF_(2)` is a monomer of

A

Nylon - 6

B

Buna - S

C

Glyptal

D

Teflon

Text Solution

Verified by Experts

The correct Answer is:
D
Teflon is also known as polytetrafluoroethene.
Promotional Banner

Topper's Solved these Questions

  • POLYMERS

    ERRORLESS|Exercise ASSERTION & REASON|4 Videos

  • POLYMERS

    ERRORLESS|Exercise NCERT BASED QUESTIONS ( BIODEGRADABLE POLYMERS)|8 Videos

  • ORGANIC COMPOUNDS CONTAINING NITROGEN

    ERRORLESS|Exercise Assertion and Reason|15 Videos

  • SOLID STATE

    ERRORLESS|Exercise ASSERTION & REASON|11 Videos

Similar Questions

Explore conceptually related problems

CF_(2) = CF_(2) is a monomer of

CH_(2)=CH_(2) is a monomer of

CF_2 = CF_2 is a unit of

Assertion : The central catbon atom in F_(2)C=C=CF_(2) and both carbo atoms in F_(2)B-Coverset(-)(=)C-BF_(2) are sp-hybridized. Reasom molecules are planar.

F_(2)C=CF-CF = CF_(2) rarr F_(2)underset(FC=)underset(|)(C)-underset(CF)underset(|)(CF_(2)) For this reaction (ring closure), DeltaH =- 49 kJ mol^(-1), DeltaS =- 40.2 J K^(-1) mol^(-1).Up to what temperature is the forward reaction spontaneous?

CF_(2)CI_(2) is used as an // a

Statement-1 : F_(2)C=C=CF_(2) molecule is having all F-atoms in one plane. Statement-2 : The molecule is non-polar.

consider the structures of the following two molecules : X : F_(2)C=C=CF_(2) Y : F_(2)B-C-=C-BF_(2) In which of these two it is impossible for all the four F-atoms to lie in the same plane ?

Fluoro carbon polymers can be made by fluorinationg polythene. (i) (CH_(2))_(n) + 4n Co F_(3) rarr (CF_(2))_(n) + 2 nHF + 4 nCoF_(2) Where n is large integer. The CoF_(3) can be regenarted by the above reaction. (ii) 2CoF_(2) + F_(2) rarr 2CoF_(3) If HF can be recovered and electrolyzed to H_(2) and if F_(2) , is used for regenerating CoF_(3) , what is the net consuption of F_(2) for 1.0 g of (CF_(2))_(n) .

Let ABC and A'B'C' be two triangles in which AB gt A'B', BC gt B'C' and CA gt C'A' . Let D, E and F be the midpoints of the sides BC, CA and AB respectively. Let D', E' and F' be the midpoints of the sides B'C', C'A' and A'B' respectively. Consider the following statements : Statement I: AD gt A'D', BE gt B'E' and CF gt C'F' are always true. Statement II : (AB^(2)+BC^(2)+CA^(2))/(AD^(2)+BE^(2)+CF^(2)) =(A'B'^(2)+B'C'^(2)+C'A'^(2))/(A'D'^(2) +B'E'^(2) +C'F'^(2)) Which one of the following is correct in respect of the above statements?