Deuterium undergoes fusion as per the reaction :
`""_(1)^(2)H+""_(1)^(2)Hto""_(2)^(3)He+""_(0)^(1)n+3.27MeV`
Find the duration for which an electric bulb of 500 W can be kept glowing by the fusion of 100 g of deuterium.

The process, ""_(1)H^(2) +""_(1)H^(3) to ""_(2)He^(4) +""_(0)n^(1) represents the types of reaction known as

Calculate the energy in fusion reaction: ""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(3) + ""_(0)n^(1) , where B.E. Of ""_(1)H^(2) = 2.23 MeV and ""_(2)He^(3) = 7.73 MeV.

Calculate the energy in the given fusion reaction. ""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(3) +n Given, B.E. of ""_(1)H^(2) = 2.23 MeV and B.E. of ""_(2)He^(3) = 7.73 MeV.

Following fusion reaction is to be used for the production of power. ""_(1)H^(2) + ""_(1)H^(2) to ""_(1)H^(3) + ""_(1)H^(1) Calculate requirem ent of mass of deuterium per day if power is produced at a rate of 10^9 W. Assume that the above process is used w ith efficiency of 50%. m(""_(1)H^(2)) = 2.01458 amu m(""_(1)H^(3)) = 3.01605 amu m(""_(1)H^(1)) = 1.00728 amu 1 amu =931 MeV//c^(2) .

In fusion reaction ._(1)H^(2) + ._(1)H^(2) to ._(2)He^(4) + Q Find the energy released while binding energy per nucleon for deuterium is 1.12 MeV and for helium nucleus is 7.07 MeV