Home
Class 12
PHYSICS
A compound microscope consists of two co...

A compound microscope consists of two converging lenses. One of them, of smaller aperture and smaller focal length is called objective and the other of slightly larger aperture and slightly larger focal length is called eye-piece. Both the lenses are fitted in a tube with an arrangement to vary the distance between them. A tiny object is placed in front of the objective at a distance slightly greater than its focal length. The objective produces the image of the object which acts as an object for the eye-piece. The eye piece, in turn produces the final magnified image.
A compound microscope consists of an objective of 10X and an eye-piece of 20X. The magnification due to the microscope would be

A

2

B

10

C

30

D

200

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • QUESTION PAPER 2022 SET - 5

    XII BOARDS PREVIOUS YEAR|Exercise SECTION-B|20 Videos
  • QUESTION PAPER 2022 SET - 4

    XII BOARDS PREVIOUS YEAR|Exercise SECTION-C|5 Videos
  • QUESTION PAPER 2022 TERM 1 SET 1

    XII BOARDS PREVIOUS YEAR|Exercise SECTION-C|6 Videos

Similar Questions

Explore conceptually related problems

The aperture and focal length of the objective of telescope are large, why?

The astronomical telescope consists of objective and eye-piece. The focal length of the objective is

The aperture and focal length of objective of microscope are small, why ?

The focal lengths of the objective and eyelens of a microscope are 1.6 cm and 2.5 cm respectively. The distance between the two lenses is 21.7 cm. If the final image is formed at infinity, the distance between the object and the objective lens is :

In compound microscope, the focal ,ength and aperture of the objective used isrespectively

The length of the tube of a microscope is 10 cm . The focal lengths of the objective and eye lenses are 0.5 cm and 1.0 cm . The magnifying power of the microscope is about

A microscope consisting of two convex lenses of focal lengths 2 cm and 5 cm placed 20 cm apart. Where must the object be placed so that the final image (virtual) is at a distance of 25 cm from eye ?