AB is a diameter of the circle with centre `O` and chord `CD` is equal to radius `OC` (fig). `AC` and `BD` proudced meet at P. Prove that `angle CPD=60^(@)`.

AB is a diameter of a circle with centre O. Chord CD is equal to radius OC. AC and BD produced intersect at P. Prove that : angleAPB= 60^(@)

ABCD is a cyclic quadrilateral of a circle with centre O such that AB is a diameter of this circle and the length of the chord CD is equal to the radius of the circle. If AD and BC produced meet at P, show that APB = 60^(@) .

In Fig. 10.32, AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E. Prove that angle AEB = 60^@ .

In the adjoinig figure, AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E. Prove that angleAEB=60^@ .

In the adjoinig figure, AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E. Prove that angleAEB=60^@ .

In Figure,AB is a diameter of a circle C(O,r)* Chord CD is equal to radius OC .If AC and BD when produced intersect at P prove that /_APB is constant.

In the given figure, AB is a diameter of the circle, CD is chord equal to the radius of the circle, AC and BD when extended intersect at a point E. Prove that angle AEB = 60^(@).

In Figure, AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E. Prove that /_A E B = 60^@

AB is diameter of a circle with centre 'O'. CD is a chord which is equal to the radius of the circle. AC and BD are extended so that they intersect each other at point P. Then find the value of angleAPB .