The amount of energy released incomplete oxidation of one molecule of glucose is

Options

A. 628 kcal
B. 668 kcal
C. 686 kcal
D. 697 kcal

Explanation

To determine the amount of energy released during the complete oxidation of one molecule of glucose, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Chemical Formula of Glucose**:
- The chemical formula for glucose is \( C_6H_{12}O_6 \).

2. **Understand the Process of Oxidation**:
- The complete oxidation of glucose occurs when it reacts with oxygen (\( O_2 \)). The products of this reaction are carbon dioxide (\( CO_2 \)) and water (\( H_2O \)), along with the release of energy.

3. **Write the Balanced Chemical Equation**:
- The balanced equation for the complete oxidation of glucose is:
\[ C_6H_{12}O_6 + 6 O_2 \rightarrow 6 CO_2 + 6 H_2O + \text{Energy} \]

4. **Determine the Amount of Energy Released**:
- The amount of energy released during the complete oxidation of one molecule of glucose is approximately \( 2870 \, \text{kJ} \).
- To convert this energy into kilocalories, we use the conversion factor where \( 1 \, \text{kJ} \) is approximately \( 0.239 \, \text{kcal} \):
\[ 2870 \, \text{kJ} \times 0.239 \, \text{kcal/kJ} \approx 686 \, \text{kcal} \]

5. **Select the Correct Option**:
- Given the options: 628, 668, 686, or 697 kcal, the correct answer is \( 686 \, \text{kcal} \), which corresponds to option C.

### Final Answer:
The amount of energy released in the complete oxidation of one molecule of glucose is **686 kcal**.

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