Solid State में Tetrahedral Void कैसे Create होता है? #shorts

In a crystalline solid, anions B arranged in ccp lattice and cations A occupy 50% of the octahedral voids. And 50% of the tetrahedral voids. What is the formula of the solid?

In a solid between A and B atoms of A are arranged in ccp array and atoms of B occupy all the octahedral voids and half of the tetrahedral voids. The formula of the compound is

Assertion (A) : A tetrahedral void is surrounded by six spheres. Reason (R) : In ionic solids, the bigger ions form the close packed structure and smaller ions occupy the voids.

In a crystalline solid, anions B are arranged in ccp structure. Cations A are equally distributed between octahedral and tetrahedral voids if all the octahedral voids are occupied the formula of the ionic solids will be

In a crystallizes solid, anions B are arranged in cubic close packing, cations A are equally distributed between octahedral and tetrahedral voids, what is the formula of the solid?

In a crystalline solid, having formula AB_(2)O_(4) oxide ions are arranged in cubic close packed lattice while cations A are present in tetrahedral voids and cations B are present in octahedral voids. (a) What percentage of the tetrahedral voids is occupied by A? (b) What percentage of the octahedral voids is occupied by B ?

For the structure of solid given below, if the lattice points represent A^(+) ions and the B^(-) ioins occupy the tetrahedral voids, then coordination number of A is :

In a crystalline solid anions B are arranged in cubic close packing. Cation A are equally distributed between octahedral and tetrahedral voids. If all the octahedral voids are occupied, the formula for the solid is