Home
Class 12
BIOLOGY
A population will not exist in Hardy-Wei...

A population will not exist in Hardy-Weinberg equilibrium if:

A

There are no mutations

B

There is no migration

C

The population is large

D

Individuals mate selectively

Text Solution

Verified by Experts

The correct Answer is:
D

To follow Hardy Weinberg law individual in a population mate randomes.
Promotional Banner

Similar Questions

Explore conceptually related problems

A population will not exist in Hardly-Weinberg equilbrium if

Assertion Mating in most natural population is random Reason Hardly-Weinberg equilibrium is successful in non-random population

Hardy Weinberg equilibrium is affected by-

A population is in Hardy-Weinberg equilibrium for a gene with only 2 alleles . If the gene frequency of an allele A is 0.7 , the genotypic frequency of homozygous recessive individuals will be

A population may get deviation from Hardy- Weinberg equilibrium. if it:

The frequency of two alleles in a gene pool is 0.19 (A) and 0.8 (a) . Assume that the population is in Hardy-Weinberg equilibrium and (a) Calculate the percentage of heterozygous individuals in the population. (b) Calculate the percentage of homozygous recessive in the population .

The frequency of two alleles in a gene pool is 0.19 ( A) and 0.81 ( a) . Assume that the population is in Hardy-Weinberg equilibrium and (a) Calculate the percentage of heterozygous individuals in the population. (b) Calculate the percentage of homozygous recessive in the population .