For .(47)Ag^(108), (Nn–Np) = 1.4 × 10^(–...

For `._(47)Ag^(108)`, (`N_n`–`N_p`) = `1.4 × 10^(–x)`. Find out x

A

0

B

1

C

-1

D

-2

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The correct Answer is:

C

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