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A man having the genotype EEFfGgHH can p...

A man having the genotype EEFfGgHH can produce P number of genetically different sperms, and a woman of genotype liLLMnNn can generate Q number of genetically different eggs. Determine the values P and Q

A

P=4, Q=4

B

P= 4 , Q= 8

C

P=8, Q=4

D

P=8, Q=8

Text Solution

Verified by Experts

The correct Answer is:
B
No. of genetically different gamete `= 2^n`
Where n refers to the no. of heterozygotes
EEFfGgHH = No. of heterozygote = 2
No. of genetically different sperm `P = 2^n = 2^2 = 4`
IiLLMmNn = No. of heterozygote = 3
No. of genetically different egg `Q= 2^3 = 8`
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