Home
Class 14
MATHS
Direction: In the given question, read t...

Direction: In the given question, read the given statement and compare the two given quantities on its basis.
Rutuja bought two articles-article A at ₹X and article B at ₹X+50. She sold article A at `20%` profit and article B at `10%` loss, and earned ₹35 as profit on the whole deal.
Quantity I. Profit earned by Rutuja on selling Article A (in ₹)
Quantity II. Loss incurred (in ₹)when an article which costs ₹480 is sold at `20%` loss

A

Quantity I `lt` Quantity II

B

Quantity I `ge` Quantity II

C

Quantity I `le` Quantity II

D

Quantity I `gt` Quantity II

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the profit earned by Rutuja on selling Article A and compare it with the loss incurred when an article costing ₹480 is sold at a 20% loss. ### Step-by-Step Solution: 1. **Identify the cost prices:** - Cost price of Article A = ₹X - Cost price of Article B = ₹X + ₹50 2. **Calculate the total cost price:** \[ \text{Total Cost Price} = X + (X + 50) = 2X + 50 \] 3. **Calculate the selling price of Article A:** - Profit on Article A = 20% - Selling Price of Article A = Cost Price + Profit \[ \text{Selling Price of A} = X + 0.20X = 1.20X = \frac{6X}{5} \] 4. **Calculate the selling price of Article B:** - Loss on Article B = 10% - Selling Price of Article B = Cost Price - Loss \[ \text{Selling Price of B} = (X + 50) - 0.10(X + 50) = 0.90(X + 50) = \frac{9(X + 50)}{10} = \frac{9X + 450}{10} \] 5. **Calculate the total selling price:** \[ \text{Total Selling Price} = \text{Selling Price of A} + \text{Selling Price of B} \] \[ = \frac{6X}{5} + \frac{9X + 450}{10} \] To add these fractions, we need a common denominator, which is 10: \[ = \frac{12X}{10} + \frac{9X + 450}{10} = \frac{12X + 9X + 450}{10} = \frac{21X + 450}{10} \] 6. **Set up the profit equation:** Rutuja earned a profit of ₹35 on the whole deal, so: \[ \text{Total Selling Price} - \text{Total Cost Price} = 35 \] \[ \frac{21X + 450}{10} - (2X + 50) = 35 \] 7. **Clear the fraction by multiplying through by 10:** \[ 21X + 450 - 20X - 500 = 350 \] \[ X - 50 = 350 \] \[ X = 400 \] 8. **Calculate the profit earned on selling Article A:** - Selling Price of Article A = \(\frac{6X}{5}\) \[ = \frac{6 \times 400}{5} = 480 \] - Profit on Article A = Selling Price - Cost Price \[ = 480 - 400 = 80 \] 9. **Calculate the loss incurred on selling an article costing ₹480 at 20% loss:** - Loss = 20% of ₹480 \[ = 0.20 \times 480 = 96 \] ### Final Comparison: - Quantity I (Profit on Article A) = ₹80 - Quantity II (Loss on ₹480 at 20% loss) = ₹96 ### Conclusion: Since ₹80 < ₹96, we conclude that: **Quantity I is less than Quantity II.**
Promotional Banner

Similar Questions

Explore conceptually related problems

A sold an article to B at 10% profit.B sold it to C at 20% profit.Find the price at which A bought if Bl's profit is Rs.44 .

Cost price of article A is Rs 200 more than the cost price of article B. Article A was sold at 10% loss and article B was sold at 25% profit. If the overall profit earned after selling both the articles is 4%, then what is the cost price of article B?

A sold an article to B at 10% profit . B sold it to c at 20% profit. Find the price at which A bought the article if B's profit is Rs 44. (in Rs)

Dhar bought two articles A and B at a total cost of Rs.8000. He sold article A at 20% profit and article B at 12% loss. In the whole deal he made no gain and no loss. At what price should Dhar have sold article B to make an overall profit of 25%? R s .5200 b. R .6400 c. R s .5800 d. R s .6200