Home
Class 14
MATHS
Direction: The question given below is f...

Direction: The question given below is followed by three statements. Study the question and the statements. Identify which option is necessary to answer the question.
A right-angled triangle is inscribed in a given circle. What is the area of the given circle (in `cm^2`)?
I. If the base and height of the triangle in cm are both roots of the equation `x^2-23x+120=0`
II. The sum of the base and the height of the triangle is 23 cm.
III. The height of the right-angled triangle is greater than the base of the same.

A

III and either only I or only II

B

All I, II and III

C

Only II and III

D

Only I

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the area of a circle in which a right-angled triangle is inscribed. The area of the circle can be calculated if we know the radius, which is half of the hypotenuse of the triangle. Let's break down the solution step by step. ### Step-by-Step Solution: 1. **Understanding the Triangle and Circle Relationship**: - A right-angled triangle inscribed in a circle has its hypotenuse equal to the diameter of the circle. Therefore, if we can find the hypotenuse of the triangle, we can find the radius of the circle. 2. **Using Statement I**: - The first statement gives us the roots of the quadratic equation \(x^2 - 23x + 120 = 0\). - To find the roots, we can factor the equation: \[ x^2 - 23x + 120 = (x - 15)(x - 8) = 0 \] - This gives us the roots \(x = 15\) and \(x = 8\). These represent the base and height of the triangle. 3. **Calculating the Hypotenuse**: - Using the Pythagorean theorem, we can find the hypotenuse (which is the diameter of the circle): \[ \text{Hypotenuse}^2 = \text{Base}^2 + \text{Height}^2 \] \[ \text{Hypotenuse}^2 = 15^2 + 8^2 = 225 + 64 = 289 \] \[ \text{Hypotenuse} = \sqrt{289} = 17 \text{ cm} \] 4. **Finding the Radius**: - The radius \(R\) of the circle is half of the hypotenuse: \[ R = \frac{17}{2} = 8.5 \text{ cm} \] 5. **Calculating the Area of the Circle**: - The area \(A\) of the circle is given by the formula: \[ A = \pi R^2 = \pi \left(\frac{17}{2}\right)^2 = \pi \left(\frac{289}{4}\right) = \frac{289\pi}{4} \text{ cm}^2 \] 6. **Conclusion**: - From the first statement alone, we were able to find the area of the circle. Therefore, Statement I is sufficient to answer the question.
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the height of the right angle triangle ? I. It is a right-angled triangle. II. The area of the triangle is 5 times its base.

The base and height of a triangle are in the ratio 3:4 and its area is 216 cm^(2) . The height of the triangle is

The base of a triangle is 15 cm and height is 12 cm. The height of another triangle of double the area having the base 20 cm is :

the base and height of the triangle are in ratio 5:4 and its area is 1000 sq.cm.find the base and height of a triangle.

Each of these questions consists of a question followed by informations in three statements. You have to study the question and the statements and decide that information in which of the statement(s) is/are necessary to answer the question. What is the area of right angled trangle ? (A) The perimeter of a triangle is 30 cm. (B) The ratio between the base and the height of the triangle is 5:12. (C ) The area of the triangle is equal to the area of a rectangle of length 10 cm.

The base of right angled triangle is 9 Cms and its area is 81 Sq Cms. What is the height of the right angled triangle?

Directions: The questions below consist of a question followed by two statements labelled l and II. You have to decide if these statements are sufficient to answer the question. Give answer What is the area of a circle? Statements: I. The radius of the circle is 7 cm. II. The circumference of the circle is 44 cm.

The height of a triangle is 2 cm less than twice its base. If the base of the triangle is 6 cm, then what is the area of the triangle?

A right angled isosceles triangle is inscribed in a semi-circle of radius 7cm. The area enclosed by the semi-circle but exterior to the triangle is: