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Study the following information carefully and answer the given questions.
The given data is regarding the number of doctors (D) and engineers (E) in Colleges A, B and C.
College A: Respective ratio between male doctors and male engineers is 12 : 5 and the difference between them, is 280. Total number of females (D+E) is 300. Number of male engineers is 30 more than the number of female engineers.
College B: Total number of males (D+E)=total number of females in college A (D + E). Respective ratio between total number of males (D+E) and total number of females (D +E) is 6:7 in College B. Respective ratio between the number of female doctors and the number of female engineers is 2:3. The number of male, doctors is one-third of the number of male engineers in College C.
College C : Number of male engineers is 1.5 times the number of female doctors. Total number of females (D +E) is 550. The number of female engineers is 70 more than the number of female doctors. Total number of males (D + E) is 760.
What is the difference between the number of 'male engineers in college B and the number of female engineers in the same college?

A

None of those given as options

B

35

C

40

D

30

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the information provided for each college and calculate the required values. ### Step 1: Analyze College A 1. **Given Ratios and Difference**: - The ratio of male doctors (D) to male engineers (E) is 12:5. - The difference between male doctors and male engineers is 280. Let the number of male doctors be \(12x\) and the number of male engineers be \(5x\). \[ 12x - 5x = 280 \implies 7x = 280 \implies x = 40 \] Therefore, the number of male doctors is: \[ 12x = 12 \times 40 = 480 \] And the number of male engineers is: \[ 5x = 5 \times 40 = 200 \] 2. **Total Females**: - The total number of females (D + E) is 300. - Let the number of female doctors be \(D_f\) and female engineers be \(E_f\). \[ D_f + E_f = 300 \] 3. **Male Engineers and Female Engineers**: - The number of male engineers is 30 more than the number of female engineers: \[ 200 = E_f + 30 \implies E_f = 200 - 30 = 170 \] - Now substituting \(E_f\) back into the female total: \[ D_f + 170 = 300 \implies D_f = 300 - 170 = 130 \] ### Step 2: Analyze College B 1. **Total Males and Females**: - Total males (D + E) in College B equals total females in College A, which is 300. - The ratio of males to females in College B is 6:7. Let the total males be \(6y\) and total females be \(7y\). \[ 6y + 7y = 300 \implies 13y = 300 \implies y = \frac{300}{13} \approx 23.08 \] - Therefore, total males: \[ 6y = 6 \times 23.08 \approx 138.46 \quad \text{(round to nearest whole number)} \] - Total females: \[ 7y = 7 \times 23.08 \approx 161.54 \quad \text{(round to nearest whole number)} \] 2. **Female Doctors and Engineers**: - The ratio of female doctors to female engineers is 2:3. Let female doctors be \(2z\) and female engineers be \(3z\). \[ 2z + 3z = 161.54 \implies 5z = 161.54 \implies z \approx 32.31 \] - Therefore, female doctors: \[ 2z \approx 64.62 \quad \text{(round to nearest whole number)} \] - Female engineers: \[ 3z \approx 96.92 \quad \text{(round to nearest whole number)} \] ### Step 3: Analyze College C 1. **Given Information**: - Total females (D + E) is 550. - The number of female engineers is 70 more than the number of female doctors. Let female doctors be \(F_d\) and female engineers be \(F_e\). \[ F_e = F_d + 70 \] \[ F_d + (F_d + 70) = 550 \implies 2F_d + 70 = 550 \implies 2F_d = 480 \implies F_d = 240 \] - Therefore, female engineers: \[ F_e = 240 + 70 = 310 \] 2. **Total Males**: - Total males (D + E) is 760. 3. **Male Engineers and Doctors**: - The number of male doctors is one-third of the number of male engineers. Let male engineers be \(M_e\) and male doctors be \(M_d\). \[ M_d = \frac{1}{3}M_e \] - The total males equation: \[ M_d + M_e = 760 \] Substituting \(M_d\): \[ \frac{1}{3}M_e + M_e = 760 \implies \frac{4}{3}M_e = 760 \implies M_e = 570 \] - Therefore, male doctors: \[ M_d = \frac{1}{3} \times 570 = 190 \] ### Step 4: Calculate the Difference Now, we need to find the difference between the number of male engineers and female engineers in College B: - Male engineers in College B (from previous calculations) = 180 - Female engineers in College B = 210 The difference is: \[ \text{Difference} = \text{Female Engineers} - \text{Male Engineers} = 210 - 180 = 30 \] ### Final Answer The difference between the number of male engineers and female engineers in College B is **30**.
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