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The unit of absolute permittivity is...

The unit of absolute permittivity is

A

Fm (farad-metre)

B

`Fm^(-1)` (farad/metre)

C

`Fm^(-2) ("farad/metre"^2)`

D

F (farad)

Text Solution

Verified by Experts

The correct Answer is:
B
`F=1/(4piepsilon_0).(q_1q_2)/(r^2)` and 1 farad `= ("1 coulomb")/("1 volt")`
`implies epsilon_0=(q_1q_2)/(4piFr^2) = ("Coulomb")/(((Nm)/("Coulomb"))m)= (1 "coulomb")/("1 volt meter")`
or `C=epsilon_0A/dimplies epsilon_0=Fm^(-1)`
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