If the dimensions of a physical quantit...

If the dimensions of a physical quantity are given by `M^(a)L^(b)T^(c)`, then the physical quantity will be :

A

Pressure if a = 1, b = -1, c = -2

B

Velocity if a = 1, b = 0, c = -1

C

Acceleration if a = 1, b = 1, c = -2

D

Force if a = 0, b = -1, c = -2

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The correct Answer is:

A

Pressure `=F/A= [ML^(-1)T^(-2)]`

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