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X=3YZ^(2) find dimension of Y in (MKSA) ...

`X=3YZ^(2)` find dimension of `Y` in (MKSA) system, if `X` and `Z` are the dimension of capacity and magnetic field respectively

A

`M^(-3) L^(-2) T^(-4) A^(-1)`

B

`ML^(-2)`

C

`M^(-3) L^(-2) T^(4) A^(4)`

D

`M^(-3) L^(-2) T^(8) A^(4)`

Text Solution

Verified by Experts

The correct Answer is:
D
`X = 3YZ^2`
`Y=(X)/(3Z^2) = ([M^(-1)L^(-2)T^(4)A^2])/([MT^(-2)A^(-1)]^2)=[M^(-2)L^(-2)T^(8) A^4]`
Capacity or capacitance
`[X] =[C] =[M^(-1)L^(-2)T^(4) A^2]`
Magnetic field [Z] `=[MT^(-2)A^(-1)]`
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