Home
Class 11
PHYSICS
Position of a body with acceleration a i...

Position of a body with acceleration `a` is given by `x=Ka^mt^n`, here t is time Find demension of m and n.

A

m = 1 , n = 1

B

= 1, n = 2

C

m = 2, n = 1

D

m = 2, n = 2

Text Solution

Verified by Experts

The correct Answer is:
B
Position of the body –
`x= ka^(m) xxt^(n)`
`[M^(0)LT^(0)]=[LT^(-2)]^(m) [T]^n =[L^mT^(-2m+n)]`
`m =1 , -2m +n = 0 implies n = 2`
Promotional Banner

Similar Questions

Explore conceptually related problems

Position of a body with acceletation a is given box x=ka^(m)t^(n) , where t is time and k is numeric constant. Find the value of m.

Completion type Question : The position of a body with respect to time is given by x = 2t^(3) - 6t^(2) + 92t + 6 . If x is in metres and t in seconds, then acceleration at t = 0 is

The position of a body with respect to time is given by x = 4t^(3) – 6t^(2) + 20 t + 12 . Acceleration at t = 0 will be-

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

The position of a particle moving in a straight line is given by x=3t^(3)-18t^(2)+36t Here, x is in m and t in second. Then

The position of a particle is given by the equation f(t)=t^(3)-6t^(2)+9t where t is measured in second and s in meter. Find the acceleration at time t. What is the acceleration at 4 s?

A particle is moving with an acceleration given by, a=-cos t ; where time t is in seconds and a is in m/s ^(2) . It is given that at t=0, u=0 and x=1 .Find distance travelled by particle from pi to 2 pi .

A particle moves such that its acceleration is given by a =- beta (x-2) Here beta is positive constant and x is the position form origin. Time period of oscillation is

A particle moves such that its acceleration is given by a = -Beta(x-2) Here, Beta is a positive constnt and x the x-coordinate with respect to the origin. Time period of oscillation is

[" If position of particle moving in straight line is "],[" given by "x=(t^(3)-2t+10)m" ,where t is time in "],[" second,then acceleration of particle at "t=1],[" sec is "......]