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The dimensions of the area A of a black ...

The dimensions of the area A of a black hole can be written in terms of the universal gravitational constant G, its mass M and the speed of light c as `A=G^(alpha)M^(beta)c^(gamma)`. Here -

A

`alpha = -2,beta = -2 and gamma = 4`

B

`alpha = 2,beta = 2 and gamma = -4`

C

`alpha = 3,beta = -3 and gamma = -2`

D

`alpha = -3,beta = -3 and gamma = 2`

Text Solution

Verified by Experts

The correct Answer is:
B

`A = G^(alpha)M^(beta)c^(gamma)`
`L^2=(M^(-1)L^3T^(-2))^(alpha)(M^1)beta(L^1T^(-1))^(gamma)`
`-alpha+beta =0 " "....(i) `
`3alpha+ gamma =2 " "...(ii)`
`-2 alpha - gamma = 0 " "....(iii)`
`alpha =2 , beta = 2 and gamma =-4`
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