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The radius of a sphere is (5.3 +- 0.1)cm...

The radius of a sphere is `(5.3 +- 0.1)`cm` The perecentage error in its volume is

A

`3+6.01 xx100/(5.3)`

B

`1/3 xx 0.01 xx100/(5.3)`

C

`((3xx0.1)/(5.3))xx100`

D

`(0.1)/(5.3) xx100`

Text Solution

Verified by Experts

The correct Answer is:
C
`r = (5.3 pm 0.1)cm`
Volume `(V) =4/3 pir^3`
`(DeltaV)/V=3(Deltar)/r ,(DeltaV)/(V) xx100 =3 ((0.1)/(5.3))xx100`
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